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標題: chem question [打印本頁]

作者: xodfg1997 時間: 2014-10-20 16:40 標題: chem question

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5識做那2條

作者: 輝輝 時間: 2014-10-20 17:53

[HCl (use in neutralize)]=2.0 x 25.0/250 =0.2
No.of moles of HCl = 0.2 x 0.025 = 0.005mol
HCl + NaOH- >H2O+NaCl
No.of moles of NaOH=No.of moles of HCl=0.005mol
[NaOH]=0.005/(12.5/1000)=0.4mol dm^-3

作者: 輝輝 時間: 2014-10-20 18:03

No.of moles of NaOH =1.5 x 0.025 = 0.0375mol
No.of moles of COOH=No.of moles of NaOH=0.0375mol
No.of moles of(COOH)2‧H2O=(1/2)No.of moles of COOH
=0.0375/2=0.01875mol
Weight of (COOH)2‧H2O=0.01875x(2(12+16+16+1)+18)=2.025g
percentage =2.025/2.5 x 100%=81%
睇完思考一次,唔好睇再做,初期畫流程圖會清晰d

作者: xodfg1997 時間: 2014-10-20 18:32

q4是否先計稀釋後hcl的m,v?

作者: 輝輝 時間: 2014-10-20 19:26

簡單黎講就係用你有既野去計先
你有齊HCl，咁就用HCl去計你唔知既野

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