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chem
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§@ªÌ:
xodfg1997
®É¶¡:
2015-6-26 19:59
¼ÐÃD:
chem
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§@ªÌ:
jasonleung28
®É¶¡:
2015-6-26 21:18
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§@ªÌ:
kyron123
®É¶¡:
2015-6-26 23:01
J=-(31.4-26.2)(4.3)(54.5)=-5.2(4.3)¡]54.5)¡×-1218.62 J¡×-1.21862kJ
¼¯º¸¼Æ¡×3.45/138=0.025mol
¤ÏÀ³2= -1.21862/0.025 =-48.75 kJ mol^-1
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