https://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-xap1/v/t1.0-9/1622657_458324400972937_4427653107426935824_n.jpg?oh=49e720c62de509eb2c4faec716234b07&oe=54AF93B2&__gda__=1425428475_2df759a855bb11c31797f4347bd550d8

5識做那2條

[HCl (use in neutralize)]=2.0 x 25.0/250 =0.2
No.of moles of HCl = 0.2 x 0.025 = 0.005mol
HCl + NaOH- >H2O+NaCl
No.of moles of NaOH=No.of moles of HCl=0.005mol
[NaOH]=0.005/(12.5/1000)=0.4mol dm^-3

No.of moles of NaOH =1.5 x 0.025 = 0.0375mol
No.of moles of COOH=No.of moles of NaOH=0.0375mol
No.of moles of(COOH)2•H2O=(1/2)No.of moles of COOH
                                                   =0.0375/2=0.01875mol
Weight of (COOH)2•H2O=0.01875x(2(12+16+16+1)+18)=2.025g
percentage =2.025/2.5 x 100%=81%
睇完思考一次,唔好睇再做,初期畫流程圖會清晰d

q4是否先計稀釋後hcl的m,v?

簡單黎講就係用你有既野去計先
你有齊HCl，咁就用HCl去計你唔知既野